x^2+10x=2184

Solution for x^2+10x=2184 equation:

x^2+10x=2184

We move all terms to the left:

x^2+10x-(2184)=0

a = 1; b = 10; c = -2184;
Δ = b2-4ac
Δ = 102-4·1·(-2184)
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-94}{2*1}=\frac{-104}{2}
=-52
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+94}{2*1}=\frac{84}{2}
=42
$